Quadratics on the Digital SAT: Factoring, Formula, Vertex & Desmos
Master Digital SAT quadratics: factoring, roots, quadratic formula, discriminant, vertex form, graph interpretation, Desmos strategy, and original practice.
Quadratics belong to Advanced Math, one of the two largest SAT Math domains.
College Board describes Advanced Math as including quadratic, exponential, polynomial, rational, radical, absolute-value, and other nonlinear relationships. So you should expect nonlinear algebra overall—but no official source guarantees a fixed number of quadratic questions.
Recognize the three useful forms
Standard form
[ y=ax^2+bx+c ]
Useful for:
- quadratic formula;
- discriminant;
- y-intercept (c).
Factored form
[ y=a(x-r_1)(x-r_2) ]
Useful for:
- roots / x-intercepts (r_1,r_2).
Vertex form
[ y=a(x-h)^2+k ]
Useful for:
- vertex ((h,k));
- minimum/maximum;
- graph transformations.
A major SAT skill is choosing the form that exposes the information you need.
Factoring
Example 1
Solve:
[ x^2-7x+12=0 ]
Find two numbers that multiply to 12 and add to -7:
-3 and -4.
[ (x-3)(x-4)=0 ]
So:
[ x=3,\ 4 ]
Difference of squares
[ x^2-25=0 ]
[ (x-5)(x+5)=0 ]
[ x=\pm5 ]
Recognizing structure is faster than using the quadratic formula.
Quadratic formula
For:
[ ax^2+bx+c=0 ]
[ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a} ]
Example 2
[ 2x^2+x-6=0 ]
(a=2,\ b=1,\ c=-6).
[ x=\frac{-1\pm\sqrt{1-4(2)(-6)}}{4} ]
[ x=\frac{-1\pm\sqrt{49}}{4} ]
[ x=\frac{-1\pm7}{4} ]
Solutions:
[ x=\frac32,\ -2 ]
This one also factors, but the formula always gives a systematic route.
The discriminant
The expression:
[ b^2-4ac ]
tells you how many real solutions a quadratic has.
- (>0): two distinct real solutions
- (=0): one repeated real solution
- (<0): no real solutions
Example 3
For what value of (k) does
[ x^2-6x+k=0 ]
have exactly one real solution?
Set discriminant to zero:
[ (-6)^2-4(1)(k)=0 ]
[ 36-4k=0 ]
[ k=9 ]
Vertex form
Example 4
[ f(x)=2(x-3)^2-5 ]
Vertex:
[ (3,-5) ]
Because (a=2>0), the parabola opens upward.
Minimum value:
[ -5 ]
The SAT may ask for:
- minimum/maximum;
- x-value at the vertex;
- transformation;
- a parameter.
Completing the square
Suppose:
[ x^2-8x+11 ]
Complete the square:
[ x^2-8x+16-5 ]
[ (x-4)^2-5 ]
Now the vertex is visible immediately:
[ (4,-5) ]
Intercepts
y-intercept
Set (x=0).
For:
[ y=3x^2-4x+7 ]
y-intercept = 7.
x-intercepts
Set (y=0) and solve.
These are the roots.
Desmos strategy
Desmos can make quadratics fast.
Find roots
Graph:
[ y=x^2-7x+12 ]
Click the x-intercepts.
Find vertex
Graph the function and inspect the turning point.
Solve a line-parabola system
Graph both equations and inspect intersections. If linear equations themselves are shakier, our linear equations guide covers the fundamentals first.
Parameter questions
A slider can help you understand behavior, but on test day algebra may be faster for exact conditions.
For a full walkthrough of when and how to use Desmos across SAT Math, see our Desmos on the Digital SAT guide.
When not to use Desmos
If:
[ (x-7)(x+2)=0 ]
the roots are visible: 7 and -2.
Opening Desmos wastes time.
Exponential vs quadratic: don't confuse them
Quadratic: [ y=x^2 ]
Exponential: [ y=2^x ]
A quadratic has a constant second difference in equally spaced x-values.
An exponential has a constant multiplicative ratio.
The SAT may test whether you can identify the model from a table.
Context problems
Example 5
The height of an object is modeled by:
[ h(t)=-16t^2+64t+5 ]
When does it reach its maximum height?
For (at^2+bt+c), vertex x-coordinate is:
[ t=-\frac{b}{2a} ]
[ t=-\frac{64}{2(-16)}=2 ]
Maximum occurs at 2 seconds.
If the question asks only when, you do not need to calculate the maximum height.
Common SAT traps
Trap 1: losing the ±
The quadratic formula usually gives two solutions.
Trap 2: wrong sign for b
If (b=-5), then (-b=+5).
Trap 3: confusing vertex with root
Vertex is not automatically an x-intercept.
Trap 4: answering a root when asked for sum/product
Read the target carefully.
Trap 5: using the longest method
Factor when structure is obvious. Graph when graphing is obvious.
Original mini-practice
1
Solve: [ x^2-9x+20=0 ]
2
How many real solutions does [ 2x^2+4x+7=0 ] have?
A. 0
B. 1
C. 2
D. infinitely many
3
The function [ f(x)=3(x+2)^2-8 ] has what minimum value?
4
For what value of (c) does [ x^2+10x+c=0 ] have exactly one real solution?
5
A parabola has roots -1 and 6 and leading coefficient 2. Which equation represents it?
A. (y=2(x+1)(x-6))
B. (y=2(x-1)(x+6))
C. (y=(x+1)(x-6))
D. (y=2(x+1)(x+6))
Answers
-
4 and 5
((x-4)(x-5)=0). -
A. 0
Discriminant (=4^2-4(2)(7)=16-56=-40). -
-8
Vertex is ((-2,-8)), and (a>0). -
25
(10^2-4c=0\Rightarrow c=25). -
A
Roots -1 and 6 correspond to factors ((x+1)(x-6)).
What to learn next
- exponential functions;
- polynomial structure;
- nonlinear systems;
- function transformations.
See the rest of our SAT Math guides for other skills.
Official references
- College Board, Advanced Math: https://satsuite.collegeboard.org/sat/whats-on-the-test/math/types/advanced
- College Board, Student Question Bank skills: https://satsuite.collegeboard.org/practice/student-question-bank/math
Trademark note: SAT® is a registered trademark of College Board. ACT® is a registered trademark of ACT Education Corp. MastaPrep is not affiliated with, endorsed by, or sponsored by College Board or ACT Education Corp.
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